Question

# If length , breadth and height of cuboid are increased by 20 %,what is the percentage increase in the the total surface area of cuboid?

Solution

## Let l, b, h be the original dimensions  New dimensions = (1.2 l), (1.2 b),(1.2 h) New total surface area = 2(lb + bh + hl) = 1.44 x 2(lb+bh+lh) ⇒ 44 % increase in the total surface area.

Suggest corrections