Question

If length, breadth and height of cuboid are increased by 40 %, what is the percentage increase in the total surface area of the cuboid?

• A. 48%
• B. 56%
• C. 96%
• D. 76%

Answer 1

The correct option is C

96%

Let l, b, h be the original dimensions

New dimensions = (1.4 l), (1.4 b), (1.4 h)

New total surface area = 2(lb + bh + hl) = 1.96 $\times$ 2(lb + bh + lh)

$\Rightarrow$ 96 $\%$ increase in the total surface area.