Question

If length of simple pendulum is increased by 6% then percentage change in time period will be?

Answer 1

$T=2\pi \sqrt{\frac{l}{g}}{l}^{\prime }\to l+0.06l=1.06l{T}^{\prime }=\sqrt{1.06}2\pi \sqrt{\frac{l}{g}}=\sqrt{1.06}T\%Change=\frac{(T^{\prime }-T)}{T}\times 100\%=\frac{(\sqrt{1.06}-1)}{1}\times 100\%=2.956\%$