If length of the diagonals of rhombus ABCD are 8 cm and 6 cm, then each of its sides is
Since diagonals of the rhombus intersect at 90∘ and they bisect each other we can find the length of the side using Pythagoras theorem.
If AC = 8 cm, BD = 6 cm, then OD = OB = 3 cm and OA = OC = 4 cm
In △ OBC,
OB2 + OC2 = BC2
32 + 42 = BC2
9 + 16 = BC2
25 = BC2
∴ BC = 5 cm
∴ Each side of the rhombus = 5cm.