If lens I has focal length + 15 cm and lens II has focal length + 30 cm, then
Given,
Focal length of lens I = + 15 cm
Focal length of lens II = + 30cm
Power of lens P=1focal length
(Plens|) = 115 = 0.06 D
(Plens||) = 130 = 0.033 D
So, (Power)lens| > (Power)lens||