Question

If letters of the word ${}^{\prime }KUBE{R}^{\prime }$ is written in all possible ways and arranged as in a dictionary then the rank of the word ${}^{\prime }KUBE{R}^{\prime }$ is,

• A. $67$
• B. $68$
• C. $69$
• D. $65$

Answer 1

The correct option is A $67$

Consider the given word.
$KUBER$

We know that

$n!=n(n-1)(n-2)(n-3).....\left(3\right)\left(2\right)\left(1\right)$

Total words starting with $B=4!=24$

Total words starting with $E=4!=24$

Total words starting with $KB=3!=6$

Total words starting with $KE=3!=6$

Total words starting with $KR=3!=6$

Start word will be $KUBER$

That rank of the word KUBER is $24+24+18+1=67$

Hence, this is the answer.