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Question

If limx0atan3x+(1cos2x)x+sinx+tanx=1, then the value of a is

A
4
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B
3
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C
2
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D
1
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Solution

The correct option is D 1
limx0atan3x+(1cos2x)x+sinx+tanx=1limx0atan3x+2sin2xx+sinx+tanx=1
Dividing the numerator and denominator by x,
limx03atan3x3x+2sin2xx1+sinxx+tanxx=13a+01+1+1=1
3a3=1a=1

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