If limx-3 x3 - cx2 - 5x - 12-x2 - 7x - 12 - lfinite real number- then

The correct options are B C = 6 D l = 4 At x=3 =27+9c+15+12/9 21+12 ⇒ 27+9c+27=0 9c= 54 ⇒ c= 6 #160;By L Hospital's Rule ...

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Substitution Method to Remove Indeterminate Form

If limx→3 ...

Question

If ${lim}_{x \to 3}$ $\frac{x^{3} + c x^{2} + 5 x + 12}{x^{2} - 7 x + 12} = l$ (finite real number), then

l = 4

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C = - 6

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C = 4

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