If limx- 2 xn - 2n-x-2 -80 - where n is a positive integer-then n-

Lim_x→ 2 (x^n) (2^n)/x 2 =n × 2^n 1 ⇒ n × 2^n 1 = 80 ⇒ n= 5 ...

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L'Hospital Rule to Remove Indeterminate Form

If limx→ 2 xn...

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If $l i m_{x \to 2}$ $\frac{(x^{n}) - (2^{n})}{x - 2}$ =80 , where n is a positive integer,
then n=

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If $l i m_{x \to 2}$ $\frac{(x^{n}) - (2^{n})}{x - 2}$ =80 , where n is a positive integer,
then n=

n

{lim}_{x \to 2} \frac{x^{n} - 2^{n}}{x - 2} = 80

n

l i m_{x \to 2} [\frac{x^{n} - 2^{n}}{x - 2}] = 32

n

sin \frac{π}{2^{n}} + cos \frac{π}{2^{n}} = \frac{\sqrt{n}}{2}

{lim}_{x \to 2} \frac{x^{n} - 2^{n}}{x - 2} = 80

n \in N

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