If line $3 x + 4 y + c = 0$ lies midway between $3 x + 4 y + 10 = 0$ $&$ $3 x + 4 y - 10 = 0$ then value of $c$ is

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Solution

The correct option is A $0$
$3 x + 4 y + 10 = 0 \to (1) 3 x + 4 y - 10 = 0 \to (2)$
line passing through midway between $(1)$ & $(2)$ is
$3 x + 4 y + \frac{10 - 10}{2} = 0$
$3 x + 4 y + 0 = 0$
Given $3 x + 4 y + c = 0$
$∴$ , $c = 0$

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