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Question

If lines px+qy+r=0,qx+ry+p=0 and rx+py+q=0 are concurrent, then the value of p+q+r is: (where p,q,r are distinct).

A
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Solution

The correct option is A 0
For concurrency of three lines
px+qy+r=0;qx+ry+p=0;rx+py+q=0
We must have, ∣ ∣pqrqrprpq∣ ∣=0
On expanding we have,
3pqrp3q3r3=0(p+q+r)(p2+q2+r2pqprrq)=0
(p+q+r)12((pq)2+(qr)2+(rp)2)
p+q+r=0 (p,q,r are distinct)

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