In △ABC,
LM || AB (Given) ⇒CLAL=CMBM [By BPT] Adding 1 on both sides we get, CLAL+1=CMBM+1 ⇒CL+ALAL=CM+BMBM ⇒CAAL=CBBM ⇒4x2x−4=2x+3x−2 ⇒4x2−8x=4x2−8x+6x−12 ⇒6x=12 ⇒x=2
If LM ∥ AB, AL=x-3, AC=2x, BM=x-2, BC=2x+3. What is value of AC?
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If LM∥AB,AL=x−3,AC=2x,BM=x−2,BC=2x+3. What is value of AC ?