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Question

If LM || AB, AL = 2x - 4, AC = 4x, BM = x - 2 and BC = 2x + 3, then x is ____.

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Solution

In ABC,

LM || AB (Given)
CLAL=CMBM [By BPT]
Adding 1 on both sides we get,
CLAL+1=CMBM+1
CL+ALAL=CM+BMBM
CAAL=CBBM
4x2x4=2x+3x2
4x28x=4x28x+6x12
6x=12
x=2


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