If $L M ∥ A B, A L = x - 3, A C = 2 x, B M = x - 2, B C = 2 x + 3.$
$Then the value of AC is$ ___

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Solution

It's given $L M ∥ A B$ ,
So, $\frac{C L}{C A} = \frac{C M}{C B}$
$\frac{(x - 3)}{2 x} = \frac{(x - 2)}{(2 x + 3)}$
$x = 9$
$S o, A C = 2 x = 18$

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