wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If log0.5 (x1)<log0.25 (x1), then x lies in the interval.


A

(2,)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

(3,)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

(,0)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

(0, 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

(2,)


log0.5 (x1)<log0.25 (x1)log0.5 (x1)<log(0.5)2 (x1)=log0.5 (x1)log0.5 (0.5)2 =12log0.5 (x1)log0.5 (x1)<0x1>1xϵ(2,)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Logarithmic Inequalities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon