Question

If ${\log }_{10}2=0.3010$, then ${\log }_{10}50$ is

Answer 1

Given

${\log }_{10}2=0.3010$

${\log }_{10}\left(\frac{100}{50}\right)=0.3010$

${\log }_{10}100-{\log }_{10}50=0.3010$

$2-{\log }_{10}50=0.3010$

${\log }_{10}50=2-0.3010$

${\log }_{10}50=1.699$