If $l o g_{10} 2 = 0.3010$ , then $l o g_{2}$ 10 is equal to

\frac{699}{301}

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\frac{1000}{301}

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0.3010

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0.6990

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Solution

The correct option is B $\frac{1000}{301}$
$l o g_{2} 10 = \frac{1}{l o g_{10} 2} = \frac{1}{0.3010} = \frac{10000}{3010} = \frac{1000}{301}$

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