If $l o g_{10} 2 = 0.30103, l o g_{10} 3 = 0.47712$ , the number of digits in $3^{12} \times 2^{8}$ is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
9

log y=12 log 3+8 log 2=8.13368

Suggest Corrections

Similar questions

l o g_{10} 2 = 0.30103, l o g_{10} 3 = 0.47712

3^{12} \times 2^{8}

{log}_{10} 2 = 0.3103, {log}_{10} 3 = 0.47712

3^{12} \times 2^{8}

0.3 < {log}_{10} 2 < 0.30103

2^{100}

{log}_{10} 2 = 0 \cdot 3010, {log}_{10} 3 = 0 \cdot 4771

5^{200}

{log}_{10} 2 = 0.3010, {log}_{10} 3 = 0.4771

6^{15}

Join BYJU'S Learning Program