If $l o g_{10} 2 = 0.30103, l o g_{10} 3 = 0.47712$ , the number of digits in $3^{12} \times 2^{8}$ is

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Solution

The correct option is C 9
log y=12 log 3+8 log 2=8.13368

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Similar questions

l o g_{10} 2 = 0.30103, l o g_{10} 3 = 0.47712

3^{12} \times 2^{8}

If $l o g_{10} 2 = 0.30103$ , then $l o g_{10} 50 =$

l o g_{10} 2 = 0.30103

l o g_{10} 50 =

l o g_{10} 2 = 0.30103

l o g_{10} 50.

[2 Marks]

{log}_{10} 2 = 0.3103, {log}_{10} 3 = 0.47712

3^{12} \times 2^{8}

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