If log102=0⋅3010,log103=0⋅4771, then the number of digits in 5200 are
A
120
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B
145
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C
160
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D
none of these
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Solution
The correct option is D none of these Let N=5200 ⇒logN=200log(5)=200(1−log2), base of the logarithm is 10. ⇒logN=200(1−0.301)=139.8 Hence, number of digits in N is 140.