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Question

If log102=a and log103=b, then express log2.25 in terms of a and b

A
2b2a
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B
ba
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C
2ba
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D
b2a
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Solution

The correct option is A 2b2a
Since , log102=a and log103=b
Consider, log2.25=log(3×32×2)=log(3222)=2log32log2=2b2a

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