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Question

If log102=a and log103=b, then express log214 in terms of a and b

A
2ba
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B
2b+2a
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C
2b2a
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D
b2a
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Solution

The correct option is D 2b2a
log102=alog103=blog214=log(3×32×2)=log(3222)=2log32log2=2b2a

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