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Question

If log102=a and log103=b, then log12 can be expressed as

A
2ab
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B
2a+2b
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C
ab
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D
2a+b
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Solution

The correct option is D 2a+b
log102=alog103=blog12=log(2×2×3)=log(22×3)=2log2+log3=2a+b

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