wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

If log10(2x+1)+2x=log106+xlog1050, then the value of x is

Open in App
Solution

log10(2x+1)+2x=log106+xlog1050
log10(2x+1)+2xxlog10(1002)=log106
log10(2x+1)+2xx(log10100log102)=log106
log10(2x+1)+2x2x+log102x=log106
log10[(2x+1)2x]=log106
2x(2x+1)=6
(2x)2+2x6=0
(2x+3)(2x2)=0
2x2=0 as 2x+30
x=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Laws of Logarithms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon