Question

If ${\log }_{10}4=0.6020$ and ${\log }_{10}9=0.9542$ then, find the value of $\log \frac{288}{128}$

Answer 1

We have,

${\log }_{10}4=0.6020$

And

${\log }_{10}9=0.9542$

Since,

$\log \frac{288}{128}$

$\Rightarrow {\log }_{10}\frac{9\times 32}{4\times 32}$

$\Rightarrow {\log }_{10}\frac{9}{4}$

$\Rightarrow {\log }_{10}9-{\log }_{10}4$

$\Rightarrow 0.9542-0.6020$

$\Rightarrow 0.3522$

Hence, this is the answer.