Question

If ${\log }_{10}4=0.6020$, find the value of:

${\log }_{10}3.2$

• A. $0.505$
• B. $0.602$
• C. $0.301$
• D. $1.505$

Answer 1

The correct option is A $0.505$

Given ${\log }_{10}4=0.6020$

Now ${\log }_{10}3.2={\log }_{10}4+{\log }_{10}0.8=0.602+{\log }_{10}8-1=0.602+\frac{3}{2}\times {\log }_{10}4-1=0.505$
[Using $4\times 0.8=32,logmn=logm+logn$ ]