If ${log}_{10} 4 = 0.6020$ , find the value of:
${log}_{10} 8$

0.301

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0.602

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0.903

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Solution

The correct option is C $0.903$
${log}_{10} 4 = 2 {log}_{10} 2 = 0.6020$
$T h e n, {log}_{10} 2 = \frac{0.6020}{2} = 0.3010$
$H e n c e, {log}_{10} 8 = {log}_{10} 2^{3} = 3 {log}_{10} 2 = 3 \times 0.3010 = 0.9030$

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