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Question

If log105=0.6990, without using log tables, find log1025,log104625,log10(13125),log5000 and log102.

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Solution

log1025=log1052=2log105=2×0.6990=1.3980
log104625=log104×25=log10100=log10102=2log1010=2
log1013125=log1055=5log105=5×0.6990=3.495
log105000=log105×103=log105+log10103=0.6990+3log1010=0.6990+3=3.6990
log102=log10105=log1010log105=10.6990=0.3010

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