If log10 7 -a- then log10 170 is equal to

The correct option is A (1 + a) log_10( #160;170) = log_10 1 log_10 70 = log_10 (7 × 10) = (log_10 7 + log_10 10) = (a + 1 ...

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Standard Logarithm

If log10 7 ...

Question

If $l o g_{10} 7 = a$ , then $l o g_{10} (\frac{1}{70})$ is equal to

- (1 + a)

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(1 + a)^{- 1}

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\frac{a}{10}

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\frac{1}{10 a}

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Solution

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Similar questions

{log}_{10} (1 + \frac{1}{2}) + {log}_{10} (1 + \frac{1}{3}) + {log}_{10} (1 + \frac{1}{4}) + . . . + {log}_{10} (1 + \frac{1}{1999})

A = [\begin{matrix} 2 & 2 9 & 4 \end{matrix}]

I = [\begin{matrix} 1 & 0 0 & 1 \end{matrix}]

10 A^{- 1}

A = [\begin{matrix} 1 & 1 0 & 1 \end{matrix}]

B [\begin{matrix} b_{1} & b_{2} b_{3} & b_{4} \end{matrix}]

10 A^{10} + a d j (A^{10}) = B

b_{1} + b_{2} + b_{3} + b_{4}

a

b

c

(10 a + b) (10 a + c)

100 a (a + 1) + b c

b

a^{2} - 10 a + b

1

a = 1

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