If ${log}_{10} a = x, {log}_{10} b = y$ , then value of $a b$ is

x y

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10^{x + y}

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100

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10^{x - y}

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Solution

The correct option is B $10^{x + y}$
${log}_{10} a = x, {log}_{10} b = y$
$a = 10^{x}, b = 10^{y}$
$a b = 10^{x + y}$

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