If ${log}_{10} e = 0.4343$ , then ${log}_{10} 1016$ is

2.99

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3

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3.006949

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3.02

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Solution

The correct option is C $3.006949$
${log}_{10} 1016 \Rightarrow \frac{log 1016}{log 10}$
$\Rightarrow \frac{3.006949}{1}$
$\to$ Option $C$ is correct

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