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Definite Integral as Limit of Sum

If log 10 7...

Question

If ${log}_{10} (7 x - 5) = 2$ , then the value of $x$ is-

A

10

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B

12

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C

15

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D

18

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Solution

The correct option is A $15$
Given that,
${log}_{10} (7 x - 5) = 2$

$⟹ 7 x - 5 = 10^{2} = 100$

$⟹ 7 x = 100 + 5$

$⟹ 7 x = 105$

$⟹ x = \frac{105}{7}$

$∴ x = 15$

Option C is correct.

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Similar questions

x = \frac{1}{(2 - \sqrt{3})}

, show that the value of (x³ − 2x² − 7x + 5) is 3.
Or
Simplify:

\frac{1}{(1 + \sqrt{2})} + \frac{1}{(\sqrt{2} + \sqrt{3})} + \frac{1}{(\sqrt{3} + \sqrt{4})} + . . . . . . + \frac{1}{(\sqrt{8} + \sqrt{9})}

x + {log}_{10} (1 + 2^{x}) = x {log}_{10} 5 + {log}_{10} 6

, then the value of

x

{log}_{10} x + {log}_{10} y = 2, x - y = 15

, then which of the following is true?

0 < x < \frac{π}{2}

cos x = \frac{3}{\sqrt{10}}

, then the value of

{log}_{10} sin x + {log}_{10} cos x + {log}_{10} tan x

l o g_{10} x - l o g_{10} \sqrt{x} = \frac{2}{l o g_{10} x}

, then value of x is

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