MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Fundamental Laws of Logarithms

If log12 27 =...

Question

If $l o g_{12} 27 = a, t h e n l o g_{6} 16 =$

A

2. \frac{3 - a}{3 + a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

3. \frac{3 - a}{3 + a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

4. \frac{3 - a}{3 + a}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

N o n e o f t h e s e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $4. \frac{3 - a}{3 + a}$
$a = \frac{l o g 27}{l o g 12} = \frac{3 l o g 3}{l o g 3 + 2 l o g 2} \Rightarrow l o g 3 = \frac{2 a l o g 2}{3 - a} l o g_{6} 16 = \frac{l o g 16}{l o g 6} = \frac{4 l o g 2}{l o g 2 + l o g 3} = \frac{4 l o g 2}{l o g 2 + \frac{2 a l o g 2}{3 - a}} = \frac{4 (3 - a)}{3 - a + 2 a} = 4. \frac{3 - a}{3 + a}$

Suggest Corrections

thumbs-up

180

Similar questions

l o g_{12} 27 = a, t h e n l o g_{6} 16 =

{log}_{12} 27 = a

{log}_{6} 16

=

{l o g}_{12} 27 = a

{l o g}_{6} 16

{log}_{12} 27 = a .

, then prove that :

{log}_{6} 16 = \frac{4 (3 - a)}{3 + a} .

{log}_{12} 27 = a

then find the value of

{log}_{6} 16

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Fundamental Laws of Logarithms

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Fundamental Laws of Logarithms

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon