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Question

If log1227=a,then log616=

A
2.3a3+a
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B
3.3a3+a
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C
4.3a3+a
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D
None of these
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Solution

The correct option is C 4.3a3+a
a=log 27log 12=3 log 3log3+2log 2log 3=2alog 23alog616=log 16log 6=4 log 2log 2+log 3=4 log 2log 2+2alog 23a=4(3a)3a+2a=4.3a3+a

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