Question

If log 2 = 0.3010 and log 3 = 0.4771, find the value of $log\sqrt{24}$

• A. 0.69005
• B. 0.605
• C. 1.69005
• D. 0.79005

Answer 1

The correct option is A

0.69005

$log\sqrt{24}$ = $log(24{)}^{\frac{1}{2}}$ = $\frac{1}{2}log(2^3\times 3)$

= $\frac{1}{2}[3\times log2+log3]$

= $\frac{1}{2}[3\times 0.3010+0.4771]$

= 0.69005