Question

If $\log 2=0.3010$ and $\log 3=0.4771$, then the value of $\log 12$ is $1.0791$.

If true then write 1 and if false then write 0

Answer 1

${\log }^{}2=0.3010{\log }^{}3=0.4771log12=log(3\times 4)2{\log }^{}2+log3=2\times 0.3010+0.4771=0.6020+0.4771=1.0791$