Question

If $\log 2=0.3010$ and $\log 3=0.4771$, then the value of $\log 15$ is $1.1761$.
If true then write 1 and if false then write 0

Answer 1

${\log }^{}2=0.3010{\log }^{}3=0.4771\log 15=\log \frac{60}{4}=\log (2\times 3\times 10)-\log 4{\log }^{}2+\log 3+1-2\log 2=0.3010+0.4771+1-2\times 0.3010=1.7781-0.6020=1.1761$