Question

If $\log 2=0.3010$ and $\log 3=0.4771$, then the value of $\log 3.6$ is $0.5562$.
If true then write 1 and if false then write 0.

Answer 1

${\log }^{}2=0.3010{\log }^{}3=0.4771\log 3.6=\log \frac{36}{10}=\log (3\times 3\times 4)-\log 102{\log }^{}2+2\log 3-1=2\times 0.3010+2\times 0.4771-1=0.6020+0.9542-1=1.5562-1=0.5562$