Question

If $\log 2=0.3010,\log 3=0.4771,\log 7=0.8451$ and $\log 11=1.0414$, then find the value of the following :
$\log 5^{1/3}$

Answer 1

$\log 5^{\frac{1}{3}}$

$=\frac{1}{3}\log 5$

$=\frac{1}{3}\log \left(\frac{10}{2}\right)$

$=\frac{1}{3}(\log 10-\log 2)$

$=\frac{1}{3}(1-0.3010)$

$=0.233$