Question

If $\log 2=0.3010,\log 3=0.4771,\log 7=0.8451$ and $\log 11=1.0414$, then find the value of the following :
$\log {\left(\frac{11}{7}\right)}^5$

Answer 1

$\log {\left(\frac{11}{7}\right)}^5$

$=5\log \left(\frac{11}{7}\right)$

$=5(\log 11-\log 7)$

$=5(1.0414-0.8451)$

$=0.9815$