Question

If $\log 2=0.3010,\log 3=0.4771,\log 7=0.8451$ and $\log 11=1.0414$, then find the value of the following :
$\log 70$

Answer 1

$\log 70$

$=\log (7\times 10)$

$=\log 7+\log 10$

$=0.8451+1$

$=1.8451$