Question

If $\log 2=0.3010,\log 3=0.4771,\log 7=0.8451$ and $\log 11=1.0414$, then find the value of the following :
$\log 36$

Answer 1

$\log 36$

$=\log 6^2$

$=2\log 6$

$=2\log (2\times 3)$

$=2\log 2+2\log 3$

$=2\left(0.3010\right)+2\left(0.4771\right)$

$=1.5562$