Question

If $\log 2=0.3010,\log 3=0.4771,\log 7=0.8451$ and $\log 11=1.0414$, then find the value of the following :
$\log \frac{42}{11}$

Answer 1

$\log \frac{42}{11}$

$=\log 42-\log 11$

$=\log (7\times 2\times 3)-\log 11$

$=\log 7+\log 2+\log 3-\log 11$

$=0.8451+0.3010+0.4771-1.0414$

$=0.5818$