Question

If $log27=1.431$, then the value of $log9$ is

• A. 0.934
• B. 0.945
• C. 0.954
• D. 0.958

Answer 1

Answer: (C)

0.954

$log27=1.431$
$\Rightarrow log\left(3^3\right)=1.431$
$\Rightarrow 3log3=1.431$
$\Rightarrow log3=0.477$
$\therefore log9=log\left(3^2\right)=2log3=(2\times 0.477)=0.954$