If log 3 2- log 32 x -5 and log 32 x -7-2 are in AP- then x is equal toA- 2B- 3C- 4D- 2-3

The correct option is B 3(2^ x 5)^2 =2 ( 2^x 7/2 ) let 2^x = t ⇒ t^2 10t + 25 = 2t 7 t^2 12t + 32 = 0 (t 8)(t 4)=0 ⇒ x = 2,3 ...

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AM,GM,HM Inequality

If log 3 2, l...

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If $l o g_{3} 2, l o g_{3} (2^{x} - 5) a n d l o g_{3} (2^{x} - \frac{7}{2})$ are in AP, then x is equal to

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