If (log3a)(logax)=5, then the value of x is equal to
A
3a
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B
243
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C
15
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D
125
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Solution
The correct option is B243 We have, (log3a)(logax)=5 By change of base rule, we get (logalog3)(logxloga)=5,[∵logab=logaloga] ⇒logxlog3=5 ∴log3x=5 ∴x=35=243