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Question

If log4=1.3868, then the approximate value of log(4.01)

A
1.3968
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B
1.3898
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C
1.3893
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D
1.9338
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Solution

The correct option is C 1.3893
Let y=f(x)=logx

Let x=4

X+x=4.01

x=0.01

For x=4

Y=log4=1.3868

y=logx

dydx=1x=14

y=dy

=dydx.dx

=14×0.01

y=0.0025

log(4.01)=y+y=1.3893

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