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Question

If log7(log5x+5+log5x+5)= 0, then find the value of x.

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Solution

log7(log5x+5+log5x+5)=0

log7(2log5x+5)=0

2logx+5=70=1

log5(x+5)=1

x+5=51=5

x=55=0

x=0.

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