If log(a+1)=log(4a−3)−log3, then the value of a is equal to
A
1
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B
6
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C
7
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D
0
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Solution
The correct option is B6 log(a+1)=log(4a−3)−log3 log(a+1)=log(4a−33) ....(∵loga=logb=logab) Since the bases of the logs are the same , then we can write (a+1)=(4a−33) 3a+3=4a−3 a=6