CameraIcon

SearchIcon

MyQuestionIcon

93

You visited us 93 times! Enjoying our articles? Unlock Full Access!

Theorems on Integration

If log a m...

Question

If ${log}_{a} m = n,$ express $a^{n - 1}$ in terms of $a$ and $m .$

Open in App

Solution

${log}_{a} m = n$
So $m = a^{n}$
$\frac{m}{a} = \frac{a^{n}}{a} = a^{n - 1}$
Hence $a^{n - 1} = \frac{m}{a}$

Suggest Corrections

thumbs-up

0

Similar questions

(a^{m})^{n} = a^{m^{n}}

^{'} m^{'}

in the terms of

^{'} n^{'}

.

l (m, n) = \int_{0}^{1} t^{m} (1 + t)^{n} d t

, then the expression for

l (m, n)

l (m + 1, n - 1)

I (m, n) = \int_{- 0}^{1} t^{m} (1 + t)^{n} d t

, then expression for

I (m, n)

I (m + 1, n - 1)

Express $l o g 135$ in terms of $m$ and $n$ if $m = l o g 15$ and $n = l o g 3$ .

l (m, n) = \int_{0}^{1} t^{m} (1 + t)^{n} d t

, then the expression for

l (m, n)

l (m + 1, n - 1)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Theorems on Integration

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Theorems on Integration

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon