Question

If $log\frac{a}{b}+log\frac{b}{a}(a+b)$, then

• A. a + b = 1
• B. a - b = 1
• C. a = b
• D. $a^2-b^2=1$

Answer 1

Answer: (A)

a + b = 1

Since, $log\frac{a}{b}+log\frac{b}{a}=log(a+b)$
$\Rightarrow log(\frac{a}{b}\times \frac{b}{a})=log(a+b)$

$\Rightarrow log1=log(a+b)$
So, $a+b=1$